Salir al pelo y compañero sin ninguna piedra de ese palo

Escenario

Esta simulación se describe así:

Jugador uno sale con un doble (X:X) y su compañero no tiene ninguna piedra con el palo X

Resultados

Luego de correr lo anterior 168 veces en el simulador, la posibilidad de que ocurra que J1 salga con X:X y su compañero no tenga ninguna piedra del palo X ocurrió 5 veces lo que corresponde a 2,97%

Código python

count_number_in_hand(hand, target_number):

"""

Counts the total occurrences of a specific number across all pieces in a player's domino hand.

"""

counter = 0

for piece in hand:

if piece[0] == target_number:

counter += 1

if piece[1] == target_number:

counter += 1

return counter

def has_double_in_hand(hand, target_number):

"""

Checks if the double piece (target_number, target_number) is present in the hand.

"""

return (target_number, target_number) in hand

scenario_counts_per_number = {}

# Iterate through each number (N) from 0 to 6

for target_num_N in range(7):

count_specific_scenario = 0

# Iterate through each simulation

for simulation_hands in all_simulations_player_hands:

p1_hand = simulation_hands[0] # Player One's hand

p3_hand = simulation_hands[2] # Player Three's hand

# Condition 1: Player One has the double tile (N,N)

p1_has_double_N = has_double_in_hand(p1_hand, target_num_N)

# Condition 2: Player One's double (N,N) is 'al pelo' (total count of N in P1's hand is exactly 2)

p1_double_N_is_al_pelo = (count_number_in_hand(p1_hand, target_num_N) == 2)

# Condition 3: Player Three does NOT have any tile with the number N

p3_has_no_N = (count_number_in_hand(p3_hand, target_num_N) == 0)

# Check if all conditions are met simultaneously

if p1_has_double_N and p1_double_N_is_al_pelo and p3_has_no_N:

count_specific_scenario += 1

scenario_counts_per_number[target_num_N] = count_specific_scenario

print("Conteo de ocurrencias del escenario específico (J1 tiene doble N 'al pelo' y J3 no tiene N) para cada número N:")

for num, count in scenario_counts_per_number.items():

print(f" Número {num}: {count} veces")

total_global_scenario_count = sum(scenario_counts_per_number.values())

print(f"\nConteo total global del escenario específico (sumando todos los números N): {total_global_scenario_count} veces")